Verified Solution • 2025–26 Session moderate

QPages 248-249: Q9: HC Verma: Concepts of Physics - Volume 2 Magnetic Field Due to a Current Pages 248-249: Q9 Solution: Two particles and having equal charge, after being accelerated…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often incorrectly assume the radius is directly proportional to mass ($r \propto m$) by ignoring that velocity depends on mass ($v \propto 1/\sqrt{m}$). Remember that $r = \frac{mv}{qB}$ combined with $v = \sqrt{\frac{2qV}{m}}$ yields $r \propto \sqrt{m}$, so the mass ratio is the square of the radius ratio.

Two particles XX and YY having equal charge, after being accelerated through the same potential difference enter a region of uniform magnetic field and describe circular paths of radii R1R_1 and R2R_2 respectively. The ratio of the mass of XX to that of YY is ______.

Multiple Choice Options

  • A R1/R2)1/2R_1/R_2)^{1/2}
  • B R1/R2R_1/R_2
  • C R1/R2)2R_1/R_2)^2
  • D R1R2R_1 R_2.

Step-by-Step Verified Solution

**Answer:** (c) (R_/R_)_. **Step-by-Step Explanation:** For the same potential difference, v _ 1/�m. r = mv/(qB) _ �m. So m _ r_. Hence m_/m_ = (R_/R_)_.

All Questions in this Chapter

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