Verified Solution • 2025–26 Session moderate

QPages 249-253: Q45: HC Verma: Concepts of Physics - Volume 2 Magnetic Field Due to a Current Pages 249-253: Q45 Solution: A circular loop of radius 4.0 cm is placed in a horizontal…

A circular loop of radius 4.0 cm is placed in a horizontal plane and carries an electric current of 5.0 A in the clockwise direction as seen from above. Find the magnetic field a) at a point 3.0 cm above the centre of the loop b) at a point 3.0 cm below the centre of the loop.

Step-by-Step Verified Solution

**Answer:** (a) B=3.14×10−5B = 3.14 \times 10^{-5} T (b) B=3.14×10−5B = 3.14 \times 10^{-5} T. **Step-by-Step Explanation:** r=0.04r = 0.04 m, i=5i = 5 A, x=0.03x = 0.03 m. B=μ0ir22(r2+x2)3/2=4π×10−7×5×0.00162(0.0016+0.0009)3/2=1.26×10−5B = \frac{\mu_0 i r^2}{2(r^2 + x^2)^{3/2}} = \frac{4\pi \times 10^{-7} \times 5 \times 0.0016}{2(0.0016 + 0.0009)^{3/2}} = 1.26 \times 10^{-5} T.

All Questions in this Chapter

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