Verified Solution • 2025–26 Session moderate

QPages 248-249: Q2: HC Verma: Concepts of Physics - Volume 2 Magnetic Field Due to a Current Pages 248-249: Q2 Solution: A current-carrying, straight wire is kept along the axis of a…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students frequently picture the magnetic field of the axial straight wire as pointing along the wire (or perpendicular to the loop), leading them to predict a net force. In reality the field forms concentric circles around the wire, i.e., it lies in the plane of the loop and is parallel to each loop element, so $d\mathbf{F}=I\,d\mathbf{l}\times\mathbf{B}=0$ and the loop experiences no force.

A current-carrying, straight wire is kept along the axis of a circular loop carrying a current. This straight wire

Multiple Choice Options

  • A will exert an inward force on the circular loop
  • B will exert an outward force on the circular loop
  • C will not exert any force on the circular loop
  • D will exert a force on the circular loop parallel to itself.

Step-by-Step Verified Solution

**Answer:** (c) will not exert any force on the circular loop. **Step-by-Step Explanation:** The magnetic field due to the straight wire is along the axis of the circular loop. The force on each element of the loop is perpendicular to both the current direction and the field. By symmetry, the net force is zero.

All Questions in this Chapter

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