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QPage 249: Q4: HC Verma: Concepts of Physics - Volume 2 Magnetic Field Due to a Current Page 249: Q4 Solution: A long, straight wire of radius carries a current distributed…
⚠️ Common Exam Traps & Conceptual Pitfalls
Students often erroneously assume the magnetic field is maximum at the wire's axis due to symmetry or confuse it with the electric field in a charged cylinder. Remember that for a uniform current distribution, $B$ is zero at the center ($r=0$) and increases linearly to a maximum at the surface ($r=R$), where it is continuous with the external field.
A long, straight wire of radius carries a current distributed uniformly over its cross section. The magnitude of the magnetic field is
Multiple Choice Options
- A maximum at the axis of the wire
- B minimum at the axis of the wire
- C maximum at the surface of the wire
- D minimum at the surface of the wire.
Step-by-Step Verified Solution
**Answer:** (b), (c).
**Step-by-Step Explanation:**
For a wire with uniform current, B = __ir/(2�R_) inside (minimum at axis) and B = __i/(2�r) outside (maximum at surface).
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