Verified Solution • 2025–26 Session moderate

QPages 249-253: Q42: HC Verma: Concepts of Physics - Volume 2 Magnetic Field Due to a Current Pages 249-253: Q42 Solution: A piece of wire carrying a current of 6.00 A is bent in the…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often insert the angle $120^circ$ directly into $B=\frac{\mu_0 I\theta}{4\pi r}$, forgetting that $\,\theta\,$ must be in radians; using degrees underestimates $B$ by a factor of $\pi/180$. Always convert the subtended angle to radians before applying the arc‑field formula.

A piece of wire carrying a current of 6.00 A is bent in the form of a circular arc of radius 10.0 cm, and it subtends an angle of 120� at the centre. Find the magnetic field B due to this piece of wire at the centre.

Step-by-Step Verified Solution

**Answer:** B=1.05×10−5B = 1.05 \times 10^{-5} T. **Step-by-Step Explanation:** i=6i = 6 A, r=0.1r = 0.1 m, θ=120�=2π/3\theta = 120� = 2\pi/3. B=μ0iθ4πr=4π×10−7×6×2π/34π×0.1=1.26×10−5B = \frac{\mu_0 i \theta}{4\pi r} = \frac{4\pi \times 10^{-7} \times 6 \times 2\pi/3}{4\pi \times 0.1} = 1.26 \times 10^{-5} T.

All Questions in this Chapter

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