Verified Solution • 2025–26 Session moderate

QPages 249-253: Q35: HC Verma: Concepts of Physics - Volume 2 Magnetic Field Due to a Current Pages 249-253: Q35 Solution: A conducting circular loop of radius is connected to two long,…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often assume that a straight current‑carrying wire contributes no magnetic field at points lying on its own line (the diameter of the loop), but the field circles the wire and is non‑zero at the loop centre. Remember to compute the $mu_0 i/(2pi a)$ contribution from each straight segment and include its direction before canceling; neglecting it leads to the incorrect $\mu_0 i/(2a)$ result.

A conducting circular loop of radius aa is connected to two long, straight wires. The straight wires carry a current ii as shown in figure. Find the magnetic field BB at the centre of the loop.

Step-by-Step Verified Solution

**Answer:** B=μ0i4aB = \frac{\mu_0 i}{4a}. **Step-by-Step Explanation:** A circular loop of radius aa connected to two long straight wires. The field at the centre due to the circular loop is μ0i2a\frac{\mu_0 i}{2a}. The field due to the straight wires at the centre is zero (since they are along the diameter). Net field: B=μ0i2aB = \frac{\mu_0 i}{2a}.

All Questions in this Chapter

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