Verified Solution • 2025–26 Session moderate

QPages 34-37: Q41: HC Verma: Concepts of Physics - Volume 2 Kinetic Theory of Gases Pages 34-37: Q41 Solution: Figure shows a cylindrical tube of cross-sectional area fitted…

Figure shows a cylindrical tube of cross-sectional area AA fitted with two frictionless pistons. The pistons are connected to each other by a metallic wire. Initially, the temperature of the gas is T0T_0 and its pressure is p0p_0 which equals the atmospheric pressure. a) What is the tension in the wire? b) What will be the tension if the temperature is increased to 2T02T_0?

Step-by-Step Verified Solution

**Answer:** (a) Tension = 0 (b) Tension = P0A2\frac{P_0 A}{2} **Step-by-Step Explanation:** (a) Initially, the gas pressure equals atmospheric pressure P0P_0. The net force on each piston is zero. So the wire tension is zero. (b) At temperature 2T02T_0 (constant volume), pressure doubles: P2=2P0P_2 = 2P_0. Force on each piston due to pressure difference: F=(P2−P0)A=P0AF = (P_2 - P_0)A = P_0 A. This force is outward on both pistons. The wire connecting them must balance these forces. By symmetry, tension in the wire T=F/2=P0A/2T = F/2 = P_0 A/2.

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