Verified Solution • 2025–26 Session moderate

QPages 34-37: Q28: HC Verma: Concepts of Physics - Volume 2 Kinetic Theory of Gases Pages 34-37: Q28 Solution: During an experiment, an ideal gas is found to obey an…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students frequently assume the usual Boyle’s law ($pV=\text{const}$) still holds and ignore the given $pV^{2}=\text{const}$, leading to an incorrect pressure‑temperature relation. Combine the new law with the ideal‑gas equation ($pV=nRT$) to obtain $nR\,T\,V=\text{const}$ (since $nR$ is constant), which shows $T\propto 1/V$ and avoids the mistake.

During an experiment, an ideal gas is found to obey an additional law

pV^2 = \text{constant}

. The gas is initially at a temperature

T

and volume

V

. Find the temperature when it expands to a volume

2V

. Use

R = 8.3 \text{ J K}^{-1} \text{ mol}^{-1}

Step-by-Step Verified Solution

**Answer:**

T_2 = T/2

**Step-by-Step Explanation:**

PV^2 = \text{constant}

. Also

PV = nRT \Rightarrow P = nRT/V

.

TV = \text{constant}

. When volume doubles, temperature halves:

T_2 = T/2

.

All Questions in this Chapter

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