Verified Solution • 2025–26 Session moderate

QPage 33: Q6: HC Verma: Concepts of Physics - Volume 2 Kinetic Theory of Gases Page 33: Q6 Solution: Figure shows graphs of pressure vs density for an ideal gas at…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often confuse the slope of a pressure-density graph with the inverse of temperature or misidentify the axes, leading to incorrect comparisons. Remember that for an ideal gas, the slope of the $P$ vs $\rho$ graph is proportional to temperature ($RT/M$), so a steeper slope indicates a higher temperature.

Figure shows graphs of pressure vs density for an ideal gas at two temperatures T1T_1 and T2T_2.

Multiple Choice Options

  • A T1>T2T_1 > T_2
  • B T1=T2T_1 = T_2
  • C T1<T2T_1 < T_2
  • D Any of the three is possible.

Step-by-Step Verified Solution

**Answer:** (a) T_ > T_. **Step-by-Step Explanation:** For an ideal gas, P = _RT/M. The slope of P vs _ is RT/M. A higher slope corresponds to a higher temperature. If T_ > T_, the graph for T_ has a steeper slope.

All Questions in this Chapter

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