Verified Solution • 2025–26 Session moderate

QPage 33: Q17: HC Verma: Concepts of Physics - Volume 2 Kinetic Theory of Gases Page 33: Q17 Solution: A vessel A has volume and a vessel B has volume . Both contain…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often incorrectly apply the Ideal Gas Law ($PV=nRT$) to the vapor, assuming that doubling the volume ($V$ to $2V$) will halve the pressure. You must recognize that in a closed vessel with liquid present, the vapor is saturated, and its pressure is determined solely by temperature, not by the available volume.

A vessel A has volume VV and a vessel B has volume 2V2V. Both contain some water which has a constant volume. The pressure in the space above water is pap_a for vessel A and pbp_b for vessel B.

Multiple Choice Options

  • A pa=pbp_a = p_b
  • B pa=2pbp_a = 2p_b
  • C pb=2pap_b = 2p_a
  • D pb=4pap_b = 4p_a

Step-by-Step Verified Solution

**Answer:** (a) p_a = p_b. **Step-by-Step Explanation:** The pressure above water in a closed vessel depends only on the temperature (saturation vapour pressure). It does not depend on the volume of the vessel. Hence, p_a = p_b if the temperatures are the same.

All Questions in this Chapter

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