Verified Solution • 2025–26 Session moderate

QPages 34-37: Q19: HC Verma: Concepts of Physics - Volume 2 Kinetic Theory of Gases Pages 34-37: Q19 Solution: Find the ratio of the mean speed of hydrogen molecules to the…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often fail to convert molar masses to kilograms per mole ($kg/mol$) when using SI units, or they incorrectly use atomic mass instead of molecular mass for diatomic gases like $H_2$ and $N_2$. Always ensure molar masses are in consistent units and reflect the molecular formula (e.g., $M_{H_2} = 2 \text{ g/mol}$, not $1 \text{ g/mol}$) before applying the ratio $v \propto 1/\sqrt{M}$.

Find the ratio of the mean speed of hydrogen molecules to the mean speed of nitrogen molecules in a sample containing a mixture of the two gases. Use R=8.314 J K−1 mol−1R = 8.314 \text{ J K}^{-1} \text{ mol}^{-1}

Step-by-Step Verified Solution

**Answer:** vH/vN=14≈3.74v_H/v_N = \sqrt{14} \approx 3.74 **Step-by-Step Explanation:** Mean speed vav∝1/Mv_{av} \propto 1/\sqrt{M}.
vHvN=MNMH=282=14≈3.74\frac{v_H}{v_N} = \sqrt{\frac{M_N}{M_H}} = \sqrt{\frac{28}{2}} = \sqrt{14} \approx 3.74

All Questions in this Chapter

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