Verified Solution • 2025–26 Session moderate

QPage 34: Q22: HC Verma: Concepts of Physics - Volume 2 Kinetic Theory of Gases Page 34: Q22 Solution: The average momentum of a molecule in a sample of an ideal gas…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often confuse the average magnitude of momentum (or kinetic energy) with the vector average. The mean momentum $langlemathbf{p} angle$ is a vector sum over all directions and therefore vanishes, independent of $T$, $n$, or $V$; only $langle|mathbf{p}| angle$ or $langle p^2 angle$ depends on temperature.

The average momentum of a molecule in a sample of an ideal gas depends on

Multiple Choice Options

  • A temperature
  • B number of moles
  • C volume
  • D none of these.

Step-by-Step Verified Solution

**Answer:** (d) none of these. **Step-by-Step Explanation:** The average momentum of a molecule in an ideal gas is zero (vector average), independent of temperature, number of moles, and volume. It is always zero.

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