Verified Solution • 2025–26 Session moderate

QPage 34: Q24: HC Verma: Concepts of Physics - Volume 2 Kinetic Theory of Gases Page 34: Q24 Solution: Consider the quantity of an ideal gas where is the mass of the…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often plug the symbols into the expression and conclude it varies with T, V or p, forgetting to replace $pV$ by $nRT$ first. After using $pV=nRT$ the $T$ cancels and the ratio reduces to $M/n\times(k/R)=\text{molecular mass}$, which is independent of temperature, volume and pressure and depends only on the gas’s nature.

Consider the quantity MkTpV\frac{MkT}{pV} of an ideal gas where MM is the mass of the gas. It depends on the

Multiple Choice Options

  • A temperature of the gas
  • B volume of the gas
  • C pressure of the gas
  • D nature of the gas.

Step-by-Step Verified Solution

**Answer:** (d) nature of the gas. **Step-by-Step Explanation:** MkT/(pV) = MkT/(nRT) = (M/n)(1/R) = m_molecule/(k) ... This depends on the molecular mass, which depends on the nature of the gas.

All Questions in this Chapter

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