Verified Solution • 2025–26 Session moderate

QPages 121-124: Q70: HC Verma: Concepts of Physics - Volume 2 Electric Field Potential Pages 121-124: Q70 Solution: A sample of HCl gas is placed in an electric field of . The…

A sample of HCl gas is placed in an electric field of 2.5×104 N C−12.5 \times 10^4 \text{ N C}^{-1}. The dipole moment of each HCl molecule is 3.4×10−30 C m3.4 \times 10^{-30} \text{ C m}. Find the maximum torque that can act on a molecule.

Step-by-Step Verified Solution

**Answer:** τmax=8.5×10−26\tau_{max} = 8.5 \times 10^{-26} N m. **STEP-BY-STEP Explanation:** p=3.4×10−30p = 3.4 \times 10^{-30} C m, E=2.5×104E = 2.5 \times 10^4 N/C.
τmax=pE=3.4×10−30×2.5×104=8.5×10−26 N m\tau_{max} = pE = 3.4 \times 10^{-30} \times 2.5 \times 10^4 = 8.5 \times 10^{-26} \text{ N m}

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