Verified Solution • 2025–26 Session moderate

QPages 121-124: Q47: HC Verma: Concepts of Physics - Volume 2 Electric Field Potential Pages 121-124: Q47 Solution: A particle of mass m and charge q is thrown at a speed u…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often equate the kinetic energy lost directly to $qEs$ without recognizing that the work done by the field is $-qEs$ when the particle moves against the field. This sign error can lead to a negative distance or a wrong dependence on the sign of $q$. Always use the magnitude of the force, $|qE|$, or explicitly write $W_{ ext{field}}=-qEs$ and set $-rac12 m u^2=W_{ ext{field}}$ to obtain $s=rac{m u^2}{2|q|E},$.

A particle of mass m and charge q is thrown at a speed u against a uniform electric field E. How much distance will it travel before coming to momentary rest?

Step-by-Step Verified Solution

**Answer:**

s = \frac{mu^2}{2qE}

. **Step-BY-STEP Explanation:** Using work-energy theorem:

\frac{1}{2}mu^2 = qEs

.

s = \frac{mu^2}{2qE}

All Questions in this Chapter

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