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QPages 121-124: Q67: HC Verma: Concepts of Physics - Volume 2 Electric Field Potential Pages 121-124: Q67 Solution: The kinetic energy of a charged particle decreases by 10 J as…

The kinetic energy of a charged particle decreases by 10 J as it moves from a point at potential 100 V to a point at potential 200 V. Find the charge on the particle.

Step-by-Step Verified Solution

**Answer:** q=−0.1q = -0.1 C. **STEP-BY-STEP Explanation:** ΔKE=−10\Delta KE = -10 J, ΔV=200−100=100\Delta V = 200 - 100 = 100 V.
qΔV=ΔKE⇒q=−10100=−0.1 Cq\Delta V = \Delta KE \Rightarrow q = \frac{-10}{100} = -0.1 \text{ C}

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