Verified Solution • 2025–26 Session moderate

QPages 121-124: Q48.1: HC Verma: Concepts of Physics - Volume 2 Electric Field Potential Pages 121-124: Q48.1 Solution: A particle of mass 1 g and charge is released from rest in an…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students frequently fail to convert the mass from grams to kilograms before calculating gravitational force, leading to an error of a factor of 1000. Always ensure mass is in SI units (kg) when applying $F_g = mg$ to maintain consistency with the electric force calculation.

A particle of mass 1 g and charge 2.5×10−4 C2.5 \times 10^{-4} \text{ C} is released from rest in an electric field of 1.2×104 N C−11.2 \times 10^4 \text{ N C}^{-1}. Find the electric force and the force of gravity acting on this particle. Can one of these forces be neglected in comparison with the other for approximate analysis?

Step-by-Step Verified Solution

**Answer:** Fe=30F_e = 30 N, Fg=0.01F_g = 0.01 N. Electric force dominates. **Step-BY-STEP Explanation:** Given: m=1m = 1 g = 10−310^{-3} kg, q=2.5×10−4q = 2.5 \times 10^{-4} C, E=1.2×104E = 1.2 \times 10^4 N/C.
Fe=qE=2.5×10−4×1.2×104=3 NF_e = qE = 2.5 \times 10^{-4} \times 1.2 \times 10^4 = 3 \text{ N}
Fg=mg=10−3×10=0.01 NF_g = mg = 10^{-3} \times 10 = 0.01 \text{ N}
Electric force is 300 times larger, so gravity can be neglected .

All Questions in this Chapter

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