Verified Solution • 2025–26 Session moderate

QPages 121-124: Q18: HC Verma: Concepts of Physics - Volume 2 Electric Field Potential Pages 121-124: Q18 Solution: A hydrogen atom contains one proton and one electron. It may be …

⚠️ Common Exam Traps & Conceptual Pitfalls

Students frequently forget to convert the radius from angstroms to meters, leading to a massive error in the denominator. Always convert $0.53$ Å to $0.53 imes 10^{-10}$ m before squaring it in Coulomb's Law.

A hydrogen atom contains one proton and one electron. It may be assumed that the electron revolves in a circle of radius 0.53 angstrom

1 \text{ angstrom} = 10^{-10} \text{ m}

and is abbreviated as

\text{\AA}

) with the proton at the centre. The hydrogen atom is said to be in the ground state in this case. Find the magnitude of the electric force between the proton and the electron of a hydrogen atom in its ground state.

Step-by-Step Verified Solution

**Answer:** Force = 8.2 _ 10__ N. **Step-BY-STEP Explanation:** Given:

r = 0.53

�

= 0.53 \times 10^{-10}

m.

F = \frac{k e^2}{r^2} = \frac{9 \times 10^9 \times (1.6 \times 10^{-19})^2}{(0.53 \times 10^{-10})^2} = 8.2 \times 10^{-8} \text{ N}

All Questions in this Chapter

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