Verified Solution • 2025–26 Session moderate

QPages 121-124: Q3: HC Verma: Concepts of Physics - Volume 2 Electric Field Potential Pages 121-124: Q3 Solution: At what separation should two equal charges, 1.0 C each, be…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often forget that taking the square root halves the exponent, so $10^7$ becomes $10^{3.5}approx10^3$. Always verify the exponent after the root and round to the correct power of ten.

At what separation should two equal charges, 1.0 C each, be placed, so that the force between them equals the weight of a 50 kg person?

Step-by-Step Verified Solution

**Answer:** Separation = 4.29 _ 10_ m. **Step-BY-Step Explanation:** Given: q1=q2=1.0q_1 = q_2 = 1.0 C, F=50×9.8=490F = 50 \times 9.8 = 490 N.
F=kq2r2⇒r2=kq2F=9×109×12490=1.836×107F = \frac{k q^2}{r^2} \Rightarrow r^2 = \frac{k q^2}{F} = \frac{9 \times 10^9 \times 1^2}{490} = 1.836 \times 10^7
r=4.29×103 mr = 4.29 \times 10^3 \text{ m}

All Questions in this Chapter

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