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QPages 121-124: Q24: HC Verma: Concepts of Physics - Volume 2 Electric Field Potential Pages 121-124: Q24 Solution: Two small spheres, each with a mass of 20 g, are suspended from …

Two small spheres, each with a mass of 20 g, are suspended from a common point by two insulating strings of length 40 cm each. The spheres are identically charged and the separation between the balls at equilibrium is found to be 4 cm. Find the charge on each sphere.

Step-by-Step Verified Solution

**Answer:** Charge = 4.12 _ 10__ C. **Step-BY-STEP Explanation:** Given: m=20m = 20 g, l=40l = 40 cm, separation d=4d = 4 cm. tan⁡θ≈sin⁡θ=240=0.05\tan\theta \approx \sin\theta = \frac{2}{40} = 0.05.
Fe=mgtan⁡θ=0.02×10×0.05=0.01 NF_e = mg\tan\theta = 0.02 \times 10 \times 0.05 = 0.01 \text{ N}
q2=Fer2k=0.01×(0.04)29×109=1.78×10−15q^2 = \frac{F_e r^2}{k} = \frac{0.01 \times (0.04)^2}{9 \times 10^9} = 1.78 \times 10^{-15}
q=4.2×10−8 Cq = 4.2 \times 10^{-8} \text{ C}

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