Verified Solution • 2025–26 Session moderate

QPages 121-124: Q53: HC Verma: Concepts of Physics - Volume 2 Electric Field Potential Pages 121-124: Q53 Solution: A uniform electric field of exists in the vertically downward…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often misuse ΔV = -∫E·dl and forget that the electric field direction matters, so they may write ΔV = -E·h and obtain a negative value. Remember that moving opposite to a downward field (i.e., upward) gives ΔV = +E h, because ΔV = -E·Δl and E·Δl is negative in this case.

A uniform electric field of 10 N C−110 \text{ N C}^{-1} exists in the vertically downward direction. Find the increase in the electric potential as one goes up through a height of 50 cm.

Step-by-Step Verified Solution

**Answer:** Increase in potential = 5 V. **Step-BY-STEP Explanation:** Electric field E=10E = 10 N/C downward. Moving up by h=0.5h = 0.5 m:
ΔV=E×h=10×0.5=5 V\Delta V = E \times h = 10 \times 0.5 = 5 \text{ V}

All Questions in this Chapter

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