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QPages 365-366: Q4: HC Verma: Concepts of Physics - Volume 2 Photoelectric Effect and Wave-Particle Duality Pages 365-366: Q4 Solution: Calculate the number of photons emitted per second by a 10 W…

Calculate the number of photons emitted per second by a 10 W sodium vapour lamp. Assume that 60% of the consumed energy is converted into light. Wavelength of sodium light = 590 nm. Use h=6.63×10−34 J-s=4.14×10−15 eV-sh = 6.63 \times 10^{-34} \text{ J-s} = 4.14 \times 10^{-15} \text{ eV-s}, c=3×108 m/sc = 3 \times 10^8 \text{ m/s} and me=9.1×10−31 kgm_e = 9.1 \times 10^{-31} \text{ kg})

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**Answer:** n=1.78×1019n = 1.78 \times 10^{19} photons/s. **Step-by-Step Explanation:** Light power = 0.6×10=60.6 \times 10 = 6 W. Energy per photon: E=1240590=2.10E = \frac{1240}{590} = 2.10 eV =2.10×1.6×10−19=3.36×10−19= 2.10 \times 1.6 \times 10^{-19} = 3.36 \times 10^{-19} J. Number of photons per second: n=63.36×10−19=1.78×1019n = \frac{6}{3.36 \times 10^{-19}} = 1.78 \times 10^{19}.

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