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QPages 365-366: Q24: HC Verma: Concepts of Physics - Volume 2 Photoelectric Effect and Wave-Particle Duality Pages 365-366: Q24 Solution: The figure is the plot of stopping potential versus the…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students frequently mistake the y-intercept (stopping potential at zero frequency) for the work function, but the work function is derived from the x-intercept (threshold frequency $\nu_0$) via $\phi = h\nu_0$. Always identify which axis intercept corresponds to the threshold condition where kinetic energy is zero.

The figure is the plot of stopping potential versus the frequency of the light used in an experiment on photoelectric effect. Find a) the ratio h/eh/e and b) the work function.

Step-by-Step Verified Solution

**Answer:** (a) h/e=4.1×10−15h/e = 4.1 \times 10^{-15} V-s (b) ϕ=2.0\phi = 2.0 eV. **Step-by-Step Explanation:** From the graph, slope =h/e= h/e. Intercept on frequency axis gives ν0\nu_0, so ϕ=hν0\phi = h\nu_0.

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