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QPages 365-366: Q19: HC Verma: Concepts of Physics - Volume 2 Photoelectric Effect and Wave-Particle Duality Pages 365-366: Q19 Solution: In an experiment on photoelectric effect, the stopping…
⚠️ Common Exam Traps & Conceptual Pitfalls
When plotting $V$ versus $1/lambda$, the independent variable must be expressed in ext{m}^{-1}. If $1/lambda$ is taken in ext{nm}^{-1}$, the slope will come out in V·nm, which cannot be directly used in $h=rac{ ext{slope},e}{c}$ because $c$ is in ext{m/s}. Convert $1/lambda$ to ext{m}^{-1}$ (or multiply the slope by $10^{-9}$) before applying the formula. Also remember that the intercept equals $-phi/e$, so the work function is $- ext{intercept} imes e$, not the intercept itself.
In an experiment on photoelectric effect, the stopping potential is measured for monochromatic light beams corresponding to different wavelengths. The data collected are as follows:- Wavelength nm): 350, 400, 450, 500, 550; Stopping potential V): 1.45, 1.00, 0.66, 0.38, 0.16. Plot the stopping potential against inverse of wavelength ) on a graph paper and find a) Planck's constant b) the work function of the emitter and c) the threshold wavelength. c) the threshold wavelength. Use , and )
Step-by-Step Verified Solution
**Answer:** (a) J-s (b) eV (c) nm.
**Step-by-Step Explanation:**
Plot vs . Slope .
From data: slope V�m. J-s.
Intercept gives eV, nm.
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