Verified Solution • 2025–26 Session moderate

QPages 363-364: Q4: HC Verma: Concepts of Physics - Volume 2 Photoelectric Effect and Wave-Particle Duality Pages 363-364: Q4 Solution: Let and be the number of photons emitted by a red bulb and a…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often incorrectly assume equal power implies equal photon counts or confuse the wavelength-frequency relationship, failing to recognize that $E = hf$ means lower frequency (red) photons carry less energy, necessitating a higher number $n$ to maintain the same total power $P$.

Let nrn_r and nbn_b be the number of photons emitted by a red bulb and a blue bulb, respectively, of equal power in a given time.

Multiple Choice Options

  • A nr=nbn_r = n_b
  • B nr<nbn_r < n_b
  • C nr>nbn_r > n_b
  • D The information is insufficient to derive a relation between nrn_r and nbn_b.

Step-by-Step Verified Solution

**Answer:** (c) n_r > n_b. **Step-by-Step Explanation:** For equal power, the number of photons n = P/E. Red photons have lower energy than blue photons, so more red photons are emitted.

All Questions in this Chapter

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