Verified Solution • 2025–26 Session moderate

QPages 363-364: Q3: HC Verma: Concepts of Physics - Volume 2 Photoelectric Effect and Wave-Particle Duality Pages 363-364: Q3 Solution: Let and denote the linear momentum and energy of a photon. If…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often confuse the direct relationship between energy and frequency with the inverse relationship between energy/momentum and wavelength. Remember that both $E = \frac{hc}{\lambda}$ and $p = \frac{h}{\lambda}$ are inversely proportional to wavelength, so decreasing $\lambda$ increases both quantities.

Let pp and EE denote the linear momentum and energy of a photon. If the wavelength is decreased,

Multiple Choice Options

  • A both pp and EE increase
  • B pp increases and EE decreases
  • C pp decreases and EE increases
  • D both pp and EE decrease

Step-by-Step Verified Solution

**Answer:** (a) both p and E increase. **Step-by-Step Explanation:** If wavelength decreases, energy E = hc/_ increases and momentum p = h/_ increases.

All Questions in this Chapter

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