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QPages 277-278: Q9: HC Verma: Concepts of Physics - Volume 2 Permanent Magnets Pages 277-278: Q9 Solution: A magnetic dipole of magnetic moment is placed horizontally…

A magnetic dipole of magnetic moment 0.72 A m20.72 \text{ A m}^2 is placed horizontally with the north pole pointing towards south. Find the position of the neutral point if the horizontal component of the earth's magnetic field is 18 _T.

Step-by-Step Verified Solution

**Answer:** d=20 cmd = 20 \text{ cm} on the axial line. **Step-by-Step Explanation:** Given: M=0.72 A m2M = 0.72 \text{ A m}^2, BH=18μTB_H = 18 \mu\text{T}. When north pole points south, neutral point is on the axial line: B=μ04π2Md3=BHB = \frac{\mu_0}{4\pi} \frac{2M}{d^3} = B_H. 18×10−6=10−7×2×0.72d3⇒d3=8×10−3⇒d=20 cm18 \times 10^{-6} = 10^{-7} \times \frac{2 \times 0.72}{d^3} \Rightarrow d^3 = 8 \times 10^{-3} \Rightarrow d = 20 \text{ cm} [citation:10].

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