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QPages 277-278: Q10: HC Verma: Concepts of Physics - Volume 2 Permanent Magnets Pages 277-278: Q10 Solution: A magnetic dipole of magnetic moment is placed horizontally…

A magnetic dipole of magnetic moment 0.722 A m20.72\sqrt{2} \text{ A m}^2 is placed horizontally with the north pole pointing towards east. Find the position of the neutral point if the horizontal component of the earth's magnetic field is 18 _T.

Step-by-Step Verified Solution

**Answer:** d=20 cmd = 20 \text{ cm} at 45� to the axis. **Step-by-Step Explanation:** Given: M=0.722 A m2M = 0.72\sqrt{2} \text{ A m}^2, BH=18μTB_H = 18 \mu\text{T}. The neutral point lies on the perpendicular bisector at distance dd. Using B=μ04πMd3=BHB = \frac{\mu_0}{4\pi} \frac{M}{d^3} = B_H gives d=20 cmd = 20 \text{ cm} [citation:10].

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