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QPages 277-278: Q3: HC Verma: Concepts of Physics - Volume 2 Permanent Magnets Pages 277-278: Q3 Solution: A uniform magnetic field of exists in the space. Find the…

A uniform magnetic field of 0.20×10−3 T0.20 \times 10^{-3} \text{ T} exists in the space. Find the change in the magnetic scalar potential as one moves through 50 cm along the field.

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**Answer:** ΔV=−0.1×10−3 T-m\Delta V = -0.1 \times 10^{-3} \text{ T-m}. **Step-by-Step Explanation:** Given: B=0.20×10−3 TB = 0.20 \times 10^{-3} \text{ T}, Δr=50 cm=0.5 m\Delta r = 50 \text{ cm} = 0.5 \text{ m}. ΔV=−B⋅Δr=−0.20×10−3×0.5=−0.1×10−3 T-m\Delta V = -B \cdot \Delta r = -0.20 \times 10^{-3} \times 0.5 = -0.1 \times 10^{-3} \text{ T-m} [citation:17].

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