Verified Solution • 2025–26 Session moderate

QPages 277-278: Q13: HC Verma: Concepts of Physics - Volume 2 Permanent Magnets Pages 277-278: Q13 Solution: The magnetic field due to the earth has a horizontal component…

The magnetic field due to the earth has a horizontal component of 26 _T at a place where the dip is 60�. Find the vertical component and the magnitude of the field.

Step-by-Step Verified Solution

**Answer:** BV=45μTB_V = 45 \mu\text{T}, B=52μTB = 52 \mu\text{T}. **Step-by-Step Explanation:** Given: BH=26μTB_H = 26 \mu\text{T}, dip δ=60�\delta = 60�. BH=Bcos⁡δ⇒B=26×10−6cos⁡60�=52μTB_H = B \cos \delta \Rightarrow B = \frac{26 \times 10^{-6}}{\cos 60�} = 52 \mu\text{T}. BV=Bsin⁡δ=52×10−6×sin⁡60�=45μTB_V = B \sin \delta = 52 \times 10^{-6} \times \sin 60� = 45 \mu\text{T} [citation:12].

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