Verified Solution • 2025–26 Session moderate

QPages 277-278: Q5: HC Verma: Concepts of Physics - Volume 2 Permanent Magnets Pages 277-278: Q5 Solution: The magnetic field at a point, 10 cm away from a magnetic…

The magnetic field at a point, 10 cm away from a magnetic dipole, is found to be

2.0 \times 10^{-4} \text{ T}

. Find the magnetic moment of the dipole if the point is a) in end-on position of the dipole and b) in broadside-on position of the dipole.

Step-by-Step Verified Solution

**Answer:** (a)

M = 1 \text{ A m}^2

(b)

M = 2 \text{ A m}^2

. **Step-by-Step Explanation:** Given:

B = 2.0 \times 10^{-4} \text{ T}

,

d = 0.1 \text{ m}

. (a) End-on:

B = \frac{\mu_0}{4\pi} \frac{2M}{d^3}

.

2 \times 10^{-4} = 10^{-7} \times \frac{2M}{0.001} \Rightarrow M = 1 \text{ A m}^2

. (b) Broadside-on:

B = \frac{\mu_0}{4\pi} \frac{M}{d^3}

.

2 \times 10^{-4} = 10^{-7} \times \frac{M}{0.001} \Rightarrow M = 2 \text{ A m}^2

[citation:17].

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