Verified Solution • 2025–26 Session moderate

QPages 275-276: Q6: HC Verma: Concepts of Physics - Volume 2 Permanent Magnets Pages 275-276: Q6 Solution: The force on a north pole, , is parallel to the field . Does it …

⚠️ Common Exam Traps & Conceptual Pitfalls

Students frequently extend the rule $\vec F\perp\vec B$ (true for the Lorentz force $\vec F = q\vec v\times\vec B$ on a moving charge) to magnetic poles, mistakenly expecting a perpendicular force. Remember that the pole model defines $\vec F = m\vec B$, which is inherently parallel to $\vec B$; the perpendicular‑only rule does not apply to hypothetical monopoles.

The force on a north pole, F⃗=mB⃗\vec{F} = m\vec{B}, is parallel to the field B⃗\vec{B}. Does it contradict our earlier knowledge that a magnetic field can exert forces only perpendicular to itself?

Step-by-Step Verified Solution

**Answer:** No, it does not contradict the earlier knowledge. **Step-by-Step Explanation:** The statement that a magnetic field can exert forces only perpendicular to itself applies to the force on a moving charge, which is F⃗=qv⃗×B⃗\vec{F} = q\vec{v} \times \vec{B}. For a magnetic pole (a hypothetical entity), the force is defined as F⃗=mB⃗\vec{F} = m\vec{B}, which is parallel to the field. This is a definition specific to the pole model and does not contradict the Lorentz force law for charges [citation:3].

All Questions in this Chapter

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