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QPages 277-278: Q20: HC Verma: Concepts of Physics - Volume 2 Permanent Magnets Pages 277-278: Q20 Solution: A deflection magnetometer is placed with its arms in…

A deflection magnetometer is placed with its arms in north-south direction. How and where should a short magnet having M/BH=40 A m2 T−1M/B_H = 40 \text{ A m}^2 \text{ T}^{-1} be placed so that the needle can stay in any position?

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**Answer:** Magnet placed 2 cm away with north pole pointing south. **Step-by-Step Explanation:** Given: M/BH=40 A m2/TM/B_H = 40 \text{ A m}^2/\text{T}. Using the formula from magnetometer theory and setting the net field to zero, d=2 cmd = 2 \text{ cm}. The magnet should be placed with its north pole pointing south [citation:4].

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