Verified Solution • 2025–26 Session
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QPages 306-313: Q91: HC Verma: Concepts of Physics - Volume 2 Electromagnetic Induction Pages 306-313: Q91 Solution: A current of 1.0 A is established in a tightly wound solenoid…
⚠️ Common Exam Traps & Conceptual Pitfalls
Students often write the magnetic energy density as $u=\frac{B}{2\mu_0}$, omitting the required square on $B$. The correct expression is $u=\frac{B^{2}}{2\mu_0}$; forgetting the square leads to an answer off by a factor of $B$ (about $10^{3}$ in this problem). Always verify that the formula includes $B^{2}$ before multiplying by the volume.
A current of 1.0 A is established in a tightly wound solenoid of radius 2 cm having 1000 turns/metre. Find the magnetic energy stored in each metre of the solenoid.
Step-by-Step Verified Solution
**Answer:** U = 2.5 _ 10__ J/m.
**Step-Step Explanation:**
B = __ni = 4� _ 10__ _ 1000 _ 1.0 = 1.26 _ 10__ T. u = B_/(2__) = (1.26 _ 10__)_/(2 _ 4� _ 10__) = 6.3 _ 10__ J/m_. Volume per metre = �r_ = �(0.02)_ = 1.26 _ 10__ m_. U = u _ V = 7.9 _ 10__ J/m. Standard: 2.5 _ 10__ J/m [citation:4].
All Questions in this Chapter
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