Verified Solution • 2025–26 Session moderate

QPages 306-313: Q12: HC Verma: Concepts of Physics - Volume 2 Electromagnetic Induction Pages 306-313: Q12 Solution: A long solenoid of radius 2 cm has 100 turns/cm and carries a…

⚠️ Common Exam Traps & Conceptual Pitfalls

When the solenoid current is reversed, the magnetic flux changes from $+\Phi$ to $-\Phi$, resulting in a total change of $\Delta\Phi = 2\Phi$. Students frequently calculate the charge using only the initial flux magnitude, thereby underestimating the result by a factor of two.

A long solenoid of radius 2 cm has 100 turns/cm and carries a current of 5 A. A coil of radius 1 cm having 100 turns and a total resistance of 20 Ω20 \ \Omega is placed inside the solenoid coaxially. The coil is connected to a galvanometer. If the current in the solenoid is reversed in direction, find the charge flown through the galvanometer.

Step-by-Step Verified Solution

**Answer:** q = 2� _ 10__ C. **Step-by-Step Explanation:** Initial flux: __ = __n i �r_. Final flux: __ = -__. __ = 2__. q = N__/R = 100 _ 2__/20 [citation:8].

All Questions in this Chapter

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