Verified Solution • 2025–26 Session moderate

QPages 303-304: Q11: HC Verma: Concepts of Physics - Volume 2 Electromagnetic Induction Pages 303-304: Q11 Solution: Two circular loops are placed with their centres separated by a …

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often treat the sign of $\cos\theta$ as giving a smaller (negative) mutual inductance, forgetting that $M$ is defined as the magnitude $M= M_{\max}|\cos\theta|$. The smallest possible mutual inductance occurs when the loop normals are perpendicular ($\theta=90^\circ$), making the flux linkage zero, not when the loops are anti‑parallel.

Two circular loops are placed with their centres separated by a fixed distance. How would you orient the loops to have a) the largest mutual inductance b) the smallest mutual inductance?

Step-by-Step Verified Solution

**Answer:** (a) Coaxial for largest mutual inductance. (b) Perpendicular axes for smallest mutual inductance. **Step-by-Step Explanation:** (a) The flux linkage is maximum when the loops are coaxial, so mutual inductance is maximum. (b) The flux linkage is zero when the axes are perpendicular, so mutual inductance is minimum [citation:1].

All Questions in this Chapter

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