Verified Solution • 2025–26 Session moderate

QPages 306-313: Q2: HC Verma: Concepts of Physics - Volume 2 Electromagnetic Induction Pages 306-313: Q2 Solution: The flux of magnetic field through a closed conducting loop…

⚠️ Common Exam Traps & Conceptual Pitfalls

When a flux is expressed as $Phi = a t^2 + b t + c$, the coefficient of $t^2$ carries units of weber per second squared ($mathrm{Wb,s^{-2}}$) because $a,t^2$ must equal $mathrm{Wb}$. The coefficient of $t$ has units of weber per second ($mathrm{Wb,s^{-1}}$). Students often mistakenly assign the same units to both $a$ and $b$, overlooking the extra time factor in $t^2$.

The flux of magnetic field through a closed conducting loop changes with time according to the equation, Φ=at2+bt+c\Phi = at^2 + bt + c. a) Write the SI units of a, b and c. b) If the magnitudes of a, b and c are 0.20, 0.40 and 0.60 respectively, find the induced emf at t = 2 s.

Step-by-Step Verified Solution

**Answer:** (a) a: Wb/s_, b: Wb/s_, c: Wb/s (b) E = 1.2 V at t = 2 s. **Step-by-Step Explanation:** (a) _ = at_ + bt + c. Since _ has units of weber, a has units of Wb/s_, b has Wb/s, and c has Wb. (b) E = d_/dt = 2at + b. At t = 2 s: E = 2(0.20)(2) + 0.40 = 0.8 + 0.4 = 1.2 V [citation:10].

All Questions in this Chapter

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