QPages 306-313: Q34: HC Verma: Concepts of Physics - Volume 2 Electromagnetic Induction Pages 306-313: Q34 Solution: A circular copper-ring of radius r translates in its plane with …
Students often treat the emf between two points as if it were the loop emf given by Faraday’s law, i.e. $$mathcal{E}=rac{dPhi}{dt},$$ and therefore look for the pair of points that encloses the largest area or the greatest flux change. In fact, for a moving conductor the motional emf between two points is $$mathcal{E}=(mathbf{v} imesmathbf{B})cdotmathbf{l},$$ where $mathbf{l}$ is the displacement vector from one point to the other. Thus the emf depends only on the component of $mathbf{l}$ perpendicular to $mathbf{v} imesmathbf{B}$, not on any enclosed area. The maximum occurs when $mathbf{l}$ is perpendicular to $mathbf{v}$ (i.e. the points are 90° apart in the direction of motion), and the minimum (zero) when $mathbf{l}$ is parallel to $mathbf{v}$.