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QPages 303-304: Q2: HC Verma: Concepts of Physics - Volume 2 Electromagnetic Induction Pages 303-304: Q2 Solution: An inductor is connected to a battery through a switch. Explain …
⚠️ Common Exam Traps & Conceptual Pitfalls
Students often treat the opening of a switch as a truly instantaneous drop of current, concluding that $V_L = L\,di/dt$ becomes infinite. In reality the current cannot change discontinuously; the voltage spike is large but finite, set by the inductance and any stray resistance or arc that appears. Remember to consider the actual $di/dt$ limited by the circuit, not an ideal “instantaneous” change.
An inductor is connected to a battery through a switch. Explain why the emf induced in the inductor is much larger when the switch is opened as compared to the emf induced when the switch is closed.
Step-by-Step Verified Solution
**Answer:** The induced emf is larger when the switch is opened because the current changes more rapidly.
**Step-by-Step Explanation:**
When the switch is closed, the current increases from zero to its steady value. When the switch is opened, the current drops from its steady value to zero almost instantaneously. The rate of change of current (di/dt) is much larger during opening than during closing. Since the induced emf is proportional to di/dt, the emf is much larger when the switch is opened.
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