Verified Solution • 2025–26 Session moderate

QPages 198-203: Q9: HC Verma: Concepts of Physics - Volume 2 Electric Current in Conductors Pages 198-203: Q9 Solution: What length of a copper wire of cross-sectional area will be…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students frequently fail to convert the cross-sectional area from $\text{mm}^2$ to $\text{m}^2$ correctly, often using $10^{-3}$ instead of the correct $10^{-6}$ factor, which leads to a length error of three orders of magnitude. Always verify that $1 \text{ mm}^2 = 10^{-6} \text{ m}^2$ before substituting into the resistance formula $R = \rho l / A$.

What length of a copper wire of cross-sectional area 0.01 mm20.01 \text{ mm}^2 will be needed to prepare a resistance of 1 kΩ1 \text{ k}\Omega? Resistivity of copper = 1.7×10−8 Ωm1.7 \times 10^{-8} \ \Omega\text{m}.

Step-by-Step Verified Solution

**Answer:** l=0.6l = 0.6 km. **Step-by-Step Explanation:** Given: A=0.01A = 0.01 mm_ =10−8= 10^{-8} m_, R=1000OmegaR = 1000\\ \\Omega, rhoCu=1.7times10−8Omegatextm\\rho_{Cu} = 1.7 \\times 10^{-8}\\ \\Omega\\text{m}. l=fracRArho=frac1000times10−81.7times10−8=588l = \\frac{RA}{\\rho} = \\frac{1000 \\times 10^{-8}}{1.7 \\times 10^{-8}} = 588 m approx0.6\\approx 0.6 km [citation:4][citation:6][citation:9].

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