Verified Solution • 2025–26 Session moderate

QPages 198-203: Q51: HC Verma: Concepts of Physics - Volume 2 Electric Current in Conductors Pages 198-203: Q51 Solution: An ammeter is to be constructed that can read currents up to…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students frequently approximate the shunt current as the total current $I$ instead of the precise difference $I - I_g$, leading to a slight overestimation of the shunt resistance. Always use the exact formula $R_s = \frac{I_g R_g}{I - I_g}$ to ensure the voltage drop across the galvanometer equals the voltage drop across the shunt.

An ammeter is to be constructed that can read currents up to 2.0 A. If the coil has resistance of

25 \ \Omega

and takes 1 mA for full-scale deflection, what should be the resistance of the shunt used?

Step-by-Step Verified Solution

**Answer:**

R_{shunt} = 0.0125\\ \\Omega

. **Step-by-Step Explanation:**

I_g = 1

mA,

R_g = 25\\ \\Omega

,

I = 2

A.

R_{shunt} = \\frac{I_g R_g}{I - I_g} = \\frac{0.001 \\times 25}{2 - 0.001} = 0.0125\\ \\Omega

[citation:2].

All Questions in this Chapter

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