Verified Solution • 2025–26 Session moderate

QPages 198-203: Q55: HC Verma: Concepts of Physics - Volume 2 Electric Current in Conductors Pages 198-203: Q55 Solution: A 6-volt battery of negligible internal resistance is connected …

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often assume the potential decreases from the positive terminal (A) to the negative terminal (B) in a linear manner, but must verify that the 4 V battery's positive terminal is connected to A, making $V_C$ positive relative to B. The trap is confusing the potential at C (4 V) with the potential drop across the wire, leading to incorrect distance calculations if the reference point (B=0) is not strictly applied to both the wire and the battery terminal.

A 6-volt battery of negligible internal resistance is connected across a uniform wire AB of length 100 cm. The positive terminal of another battery of emf 4 V and internal resistance 1 Ω1 \ \Omega is joined to the point A, as shown in the figure. Take the potential at B to be zero. a) What are the potentials at the points A and C? b) At which point D of the wire AB, the potential is equal to the potential at C? c) If the points C and D are connected by a wire, what will be the current through it? d) If the 4 V battery is replaced by a 7.5 V battery, what would be the answers of parts a) and b)?b)?

Step-by-Step Verified Solution

**Answer:** (a) VA=6V_A = 6 V, VC=4V_C = 4 V (b) AD=66.7AD = 66.7 cm (c) i=0.4i = 0.4 A (d) New values. **Step-by-Step Explanation:** (a) VA=6V_A = 6 V (at positive terminal), VC=4V_C = 4 V (at 4 V battery). (b) Point D where potential equals VCV_C: AD=(4/6)times100=66.7AD = (4/6) \\times 100 = 66.7 cm. (c) Current through CD when connected [citation:2].

All Questions in this Chapter

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