Verified Solution • 2025–26 Session moderate

QPages 198-203: Q69: HC Verma: Concepts of Physics - Volume 2 Electric Current in Conductors Pages 198-203: Q69 Solution: A 100 _F capacitor is joined to a 24 V battery through a…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often mistakenly assume the capacitor is fully charged at $t = 10$ minutes, ignoring that the time constant $\tau = RC = 100 \text{ s}$ means the system reaches steady state in roughly $5\tau = 500 \text{ s}$ (about 8.3 minutes). The graph must explicitly show the current decaying to near zero and the charge plateauing at $C\varepsilon$ well before the 10-minute mark, rather than continuing to change linearly or exponentially throughout the entire duration.

A 100 _F capacitor is joined to a 24 V battery through a 1.0 MΩ1.0 \text{ M}\Omega resistor. Plot qualitative graphs a) between current and time for the first 10 minutes and b) between charge and time for the same period.

Step-by-Step Verified Solution

**Answer:** Qualitative graphs. **Step-by-Step Explanation:** (a) i(t)=i0e−t/taui(t) = i_0 e^{-t/\\tau}: exponential decay. (b) q(t)=Cvarepsilon(1−e−t/tau)q(t) = C\\varepsilon(1 - e^{-t/\\tau}): exponential rise [citation:2].

All Questions in this Chapter

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