Verified Solution • 2025–26 Session moderate

QPages 198-203: Q66: HC Verma: Concepts of Physics - Volume 2 Electric Current in Conductors Pages 198-203: Q66 Solution: A capacitor of capacitance 8.0 _F is connected to a battery of…

A capacitor of capacitance 8.0 _F is connected to a battery of emf 6.0 V through a resistance of 24 Ω24 \ \Omega. Find the current in the circuit a) just after the connections are made and b) one time constant after the connections are made.

Step-by-Step Verified Solution

**Answer:** (a) i=0.25i = 0.25 A (b) i=0.092i = 0.092 A. **Step-by-Step Explanation:** C=8mutextFC = 8\\ \\mu\\text{F}, varepsilon=6\\varepsilon = 6 V, R=24OmegaR = 24\\ \\Omega. (a) At t=0t = 0: i=varepsilon/R=6/24=0.25i = \\varepsilon/R = 6/24 = 0.25 A. (b) At t=taut = \\tau: i=i0e−1=0.25times0.368=0.092i = i_0 e^{-1} = 0.25 \\times 0.368 = 0.092 A [citation:2].

All Questions in this Chapter

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