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QPages 198-203: Q15: HC Verma: Concepts of Physics - Volume 2 Electric Current in Conductors Pages 198-203: Q15 Solution: The current in a conductor and the potential difference across…

⚠️ Common Exam Traps & Conceptual Pitfalls

When a voltmeter has a zero error, its reading is the true voltage plus the error: $V_{ ext{read}}=V_{ ext{true}}+V_0$. Thus the true voltage is $V_{ ext{true}}=V_{ ext{read}}-V_0$, not $V_{ ext{read}}+V_0$. Using the wrong sign in the equation $(V_{ ext{read}}pm V_0)/I$ leads to an incorrect zero error. Always subtract the error from the reading before applying Ohm’s law.

The current in a conductor and the potential difference across its ends are measured by an ammeter and a voltmeter. The meters draw negligible currents. The ammeter is accurate but the voltmeter has a zero error that is, it does not read zero when no potential difference is applied). Calculate the zero error if the readings for two different conditions are 1.75 A, 14.4 V and 2.75 A, 22.4 V.

Step-by-Step Verified Solution

**Answer:** Zero error = 0.4 V. **Step-by-Step Explanation:** Let the voltmeter reading be V′=V+V0V' = V + V_0 where V0V_0 is the zero error. frac14.4−V01.75=frac22.4−V02.75\\frac{14.4 - V_0}{1.75} = \\frac{22.4 - V_0}{2.75}. Solving gives V0=0.4V_0 = 0.4 V [citation:5][citation:12].

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