Verified Solution • 2025–26 Session moderate

QPages 230-234: Q7: HC Verma: Concepts of Physics - Volume 2 Magnetic Field Pages 230-234: Q7 Solution: Consider a 10-cm long portion of a straight wire carrying a…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students frequently insert the 10‑cm wire length as 10 instead of converting it to metres (0.10 m) in $F=ILB\sin\theta$, which inflates the force by a factor of 100. Always express length in SI units before applying the magnetic force formula.

Consider a 10-cm long portion of a straight wire carrying a current of 10 A placed in a magnetic field of 0.1 T making an angle of 53� with the wire. What magnetic force does the wire experience?

Step-by-Step Verified Solution

**Answer:** F=4.8 NF = 4.8 \text{ N}. **Step-by-Step Explanation:** F=ilBsin⁡θ=10×0.1×0.1×sin⁡53∘=0.1×0.8=0.08 NF = i l B \sin\theta = 10 \times 0.1 \times 0.1 \times \sin 53^\circ = 0.1 \times 0.8 = 0.08 \text{ N}.

All Questions in this Chapter

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