Verified Solution • 2025–26 Session moderate

QPages 230-234: Q18: HC Verma: Concepts of Physics - Volume 2 Magnetic Field Pages 230-234: Q18 Solution: A wire, carrying a current , is kept in the plane along the…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often replace $\int\!dl$ with the curve’s arc length, assuming $F=iB\times$(arc length). In reality $d\mathbf F=i\,\mathbf{dl}\times\mathbf B$, so only the component of $\mathbf{dl}$ perpendicular to $\mathbf B$ contributes; the net force equals $iB$ times the projection of the wire onto the $x$‑axis, not its total curved length.

A wire, carrying a current ii, is kept in the x−yx - y plane along the curve y=Asin⁡2πx/λ)y = A \sin2\pi x / \lambda). A magnetic field BB exists in the zz direction. Find the magnitude of the magnetic force on the portion of the wire between x=0x = 0 and x=λx = \lambda.

Step-by-Step Verified Solution

**Answer:** F=iBλF = i B \lambda. **Step-by-Step Explanation:** The wire follows the curve y=Asin⁡(2πx/λ)y = A \sin(2\pi x/\lambda) from x=0x = 0 to x=λx = \lambda. The net displacement in the y-direction is zero. The effective length is λ\lambda along the x-axis. F=iBλF = i B \lambda.

All Questions in this Chapter

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