Verified Solution • 2025–26 Session moderate

QPages 230-234: Q58: HC Verma: Concepts of Physics - Volume 2 Magnetic Field Pages 230-234: Q58 Solution: A square coil of edge and with turns carries a current . It is…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often incorrectly assume the magnetic torque acts about the center or forget that the effective lever arm for the vertical force component is half the side length ($l/2$), leading to a missing factor of 2 in the denominator.

A square coil of edge ll and with nn turns carries a current ii. It is kept on a smooth horizontal plate. A uniform magnetic field BB exists parallel to an edge. The total mass of the coil is MM. What should be the minimum value of BB for which the coil will start tipping over?

Step-by-Step Verified Solution

**Answer:** Bmin=Mg2nil2B_{min} = \frac{M g}{2 n i l^2}. **Step-by-Step Explanation:** For the coil to start tipping, the torque due to magnetic force must equal the torque due to gravity about the edge.

All Questions in this Chapter

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