Verified Solution • 2025–26 Session moderate

QPages 230-234: Q61: HC Verma: Concepts of Physics - Volume 2 Magnetic Field Pages 230-234: Q61 Solution: Consider a solid sphere of radius and mass that has a charge…

⚠️ Common Exam Traps & Conceptual Pitfalls

When computing the magnetic moment of a uniformly charged rotating sphere, students frequently drop the prefactor ½ in the definition $\mu=\tfrac12\int \mathbf r\times\mathbf J\,dV$, or they replace the volume current by a surface current. This omission removes the essential factor that balances the $\tfrac{2}{5}$ moment‑of‑inertia term, leading to an incorrect $\mu$‑to‑$L$ ratio.

Consider a solid sphere of radius rr and mass mm that has a charge qq distributed uniformly over its volume. The sphere is rotated about its diameter with an angular speed ω\omega. Show that the magnetic moment μ\mu and the angular momentum ll of the sphere are related as μ=q2ml\mu = \frac{q}{2m} l.

Step-by-Step Verified Solution

**Answer:** μ=q2mL\mu = \frac{q}{2m} L. **Step-by-Step Explanation:** For a rotating solid sphere, integrate over volume. The result is the same universal ratio.

All Questions in this Chapter

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