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QPages 229-230: Q5: HC Verma: Concepts of Physics - Volume 2 Magnetic Field Pages 229-230: Q5 Solution: A charged particle moves along a circle under the action of…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often mistakenly assume a uniform electric field can sustain circular motion, but a constant $E$ produces a constant acceleration vector that results in parabolic (projectile-like) trajectories, not closed circular paths. Only a magnetic field, which exerts a force always perpendicular to velocity ($F = qvB$), can provide the continuously rotating centripetal force required for uniform circular motion.

A charged particle moves along a circle under the action of possible constant electric and magnetic fields. Which of the following is possible?

Multiple Choice Options

  • A E=0,B=0E = 0, B = 0
  • B E=0,B≠0E = 0, B \neq 0
  • C E≠0,B=0E \neq 0, B = 0
  • D E≠0,B≠0E \neq 0, B \neq 0

Step-by-Step Verified Solution

**Answer:** (b) E = 0, B � 0. **Step-by-Step Explanation:** For circular motion, a magnetic field perpendicular to velocity provides the centripetal force. E = 0.

All Questions in this Chapter

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